Question

A train after travelling 50 km meets with an accident and then proceeds at 3/4of its usual speed

Answer 1

$speed \: \: of \: \: train \: \: after \: \: accident = 37.5 \: km/h$

Explanation:

$A/Q, \: speed \: \: of \: \: train \: \: after \: \: accident \\ 50 \: km/h \times \frac{3}{4} = 37.5 \: km/h$