Question

A train approaching a crossing changes speed from 10 m/s to 25 m/s in 240 s. How can the train's acceleration be described?

Answer 1

Given ---
Initial velocity (u) = 10 m/s
Final velocity (v) = 25 m/s
Time taken (t) = 240 s

To find ---
Acceleration (a)

Finding ---

We know that acceleration is the rate of change of velocity, i.e.,

$a = \frac{v - u}{t}$

$= > a = \frac{25 - 10}{240}$

$= > a = \frac{15}{240}$

$= > a = 0.625$
Hence, the train's acceleration is 0.625 m/s²

Hope it'll help. :-)

Answer 2

u=10m/s
v=25m/s
t=240sec
a=?

25×25-10×10=2×a×240
625-100=480a
525=480a
1.09=a

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