Question

A train begins a journey from a
station and travels 60km in a time of 20 minutes. What is the average speed of the train.​

Answer 1

Answer:

The Average Speed Of the Train = 50 meter per second.

Explanation:

Given:-

Total distance of journey of the train = 60 km.

Time taken to complete the journey = 20 minutes.

To Find:-

The Average speed of the train (in meters).

Formula Used:-

{\rm\longrightarrow\boxed{\bf S = \dfrac{D}{T}.}}⟶

S=

T

D

.

Where,

S = Speed.

D = Distance.

T = Time.

Concepts Used:-

1 kilometer = 100 meters.

1 Minute = 60 Seconds.

So Now,

\because∵ We have to Find out the Average speed in meter per second So let us first convert 60 km in meters amd 20 minutes in seconds.

\tt\mapsto 1 \: km = 1000 \: m.↦1km=1000m.

\tt\mapsto1 \: km\times 60 = 1000 \: m \times 60.↦1km×60=1000m×60.

\rm\big(multiplying \: \: 60 \: \: both \: \: the \: \: sides \big).(multiplying60boththesides).

{\bf\mapsto \boxed{ \bf60 \: km = 60000 \: m.}}↦

60km=60000m.

Similarly,

\tt\mapsto1 \: \: min = 60 \: \: sec↦1min=60sec

\tt\mapsto1 \: \: min \times 20 = 60 \: \: sec \times 20.↦1min×20=60sec×20.

\rm \big(multiplying \: \: 20 \: \: both \: \: sides \big).(multiplying20bothsides).

{ \bf\mapsto \boxed{ \bf20 \: \: min = 1200 \: \: sec.}}↦

20min=1200sec.

Therefore,

{\underline{\underline{\bf Average \ \ Speed\ \ Of\ \ The\ \ Train:-}}}

Average Speed Of The Train:−

\tt = \dfrac{600 \cancel{00} \: \: \cancel{m}}{12 \cancel{00} \: \: \cancel{sec}} .=

12

00

sec

600

00

m

.

\tt = \dfrac{ \cancel{600} \: \: {}^{50} }{ \cancel{12} \: \: _1}=

12

1

600

50

{ \boxed{ \bf =50 \: m/s}}

=50m/s

\large\bf\therefore∴ The Average Speed Of the Train = 50 meter per second