Question

A train covered 36 3/4km the first hour, 40 2/5 km the second hour and 38 km in third hour. find the total distance travelled by the train m 3 hours.​

Answer 1

The total distance travelled by the train in 3 hours is 115.15 km

Solution:

Given that,

$First\ hour = 36\frac{3}{4}\ km\\\\Second\ hour = 40\frac{2}{5}\ km\\\\Third\ hour = 38\ km$

Convert to decimal

$First\ hour = 36\frac{3}{4} = \frac{4 \times 36+3}{4} = \frac{147}{4} = 36.75\\\\Second\ hour = 40\frac{2}{5} = \frac{5 \times 40+2}{5} = \frac{202}{5} = 40.4$

Find the total distance travelled by the train in 3 hours

$Total\ distance = first\ hour + second\ hour + third\ hour\\\\Total\ distance = 36.75+40.4+38\\\\Total\ distance = 115.15$

Thus the total distance travelled by the train in 3 hours is 115.15 km

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Answer 2

Answer:

Solution:

Given that

First hour = 36 3/4km

Second hour = 40/25km

Third\ hour = 38 km

First hour=36

4

3

km

Second hour=40

5

2

km

Third hour=38 km

Convert to decimal

\begin{gathered}First\ hour = 36\frac{3}{4} = \frac{4 \times 36+3}{4} = \frac{147}{4} = 36.75\\\\Second\ hour = 40\frac{2}{5} = \frac{5 \times 40+2}{5} = \frac{202}{5} = 40.4\end{gathered}

First hour=36

4

3

=

4

4×36+3

=

4

147

=36.75

Second hour=40

5

2

=

5

5×40+2

=

5

202

=40.4

Find the total distance travelled by the train in 3 hours

\begin{gathered}Total\ distance = first\ hour + second\ hour + third\ hour\\\\Total\ distance = 36.75+40.4+38\\\\Total\ distance = 115.15\end{gathered}

Total distance=first hour+second hour+third hour

Total distance=36.75+40.4+38

Total distance=115.15

Thus the total distance travelled by the train in 3 hours is 115.15 km