a train covered a certain distance at a uniform speed. if the train would have been 10km/hr faster, it would have taken 1 hour less than the scheduled time. and if the train were slower by 6km/hr, it would have taken 1 hour more than the scheduled time. find the length of the journey.
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x/10+1=x/6-1
x/6-x/10=2
x(10-6)/60=2
x=2*60/4
x=30km
x/6-x/10=2
x(10-6)/60=2
x=2*60/4
x=30km
nishartk2007p9sdlo:
are u sure about your ans.
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