Question

A train does a journey without stopping in 8 hours. if it had traveled 5 km an hour faster, it would have done the journey in 6 hours 40 min. what is its slower speed?

Answer 1

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Answer 2

Answer:

25 km / hr

Step-by-step explanation:

Let the speed of the train be x km/hr

Time taken by train = 8 hours

$Distance = Speed \times Time$

$Distance =8x$

Now we are given that if it had traveled 5 km an hour faster, it would have done the journey in 6 hours 40 min.

So, New Speed = x+5

Time = 6 hours 40 min = $\frac{20}{3} hours$

$Distance = (x+5) \times \frac{20}{3}$

Distance will remain same

So, $(x+5) \times \frac{20}{3} =8x$

$\frac{20}{3}x+ \frac{100}{3} =8x$

$\frac{100}{3} =8x-\frac{20}{3}x$

$\frac{100}{3} =\frac{4}{3}x$

$\frac{100 \times 3}{3 \times 4} =x$

$25=x$

Hence the slower speed is 25 km / hr