Question

A train first travels for 120 min with a speed of 30km/hr and then for 180 min with a speed of40km/hr in the same direction. Calculate (a) the total distance travelled.(b) the average speed of the train.

Answer 1

Answer:

spped of first train 30 km /h

time 120 min

change into h= 120 / 60

== 2h

distance 30 × 2 = 60 km/h. (d1)

speed of sec train 40 km / h

time 180 min

change into h 180 / 60

====3

distance = 40 ×3

===== 120 km/ h (d2)

total distance (d1 ) + ( d2)

120 + 60

180km /h

average speed. 40km/h + 30 km/h÷2

35 km/h