Question

A train from rest moves with a uniform acceleration of 0.2meter per second square for 5 min .calculate the final velocity and the distance traveled in this time

Answer 1

Answer :-

v = 60m/s

s = 9,000m

Given:-

u = 0

a = 0.2 m /s²

T = 5 minutes = 300 s

To find :-

It's Final velocity (v) and distance travelled.

Answer :-

Since, it is given here acceleration is constant so, we can use equation of motion.

From first equation of motion,

$v = u + at$

$v = 0 + 0.2 \times 300$

$v = 60 m/s$

Now , we have v = 60m/s.

Using 3 rd equation of motion,

$2as = v^2 - u^2$

$2 \times 0.2 \times s = (60) ^2 - (0)^2$

$0.4 \times s = 3600$

$s = \dfrac {3600}{0.4}$

$s = 9,000m$

hence, final velocity = 60m/s

and distance travelled = 9,000m.