Question

A train goes to a station A to another station B at a speed for 64km/hr but return to a at slowest speed the average speed of trip is 56km/h the return speed of train

Answer 1

Average Speed = (2×A×B)/ (A+B)

Average Speed = 56
A= 64
B=?

56= 2× 64× B/ (64+B)

7×(64+B)= 16B

448+7B= 16B

9B= 448

B= 49.77

Speed for Return Journey is 49.77 km/h

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Answer 2

Answer:

Step-by-step explanation:

Average Speed = (2×A×B)/ (A+B)

Average Speed = 56

A= 64

B=?

56= 2× 64× B/ (64+B)

7×(64+B)= 16B

448+7B= 16B

9B= 448

B= 49.77

Speed for Return Journey is 49.77 km/h or 50km/hr (approx)