Question

A train has to negotiate a curve of radius 400 m. By how much should the outer rail be raised w.r.t. inner rail for a speed of 72 km/h, if distance between the rails is 1.5 m (g = 10 m/s2)

Answer 1

Answer:

Radius of curved path is r. width of path is b m. the outer edge is raised by h w.r.t inner edge so that a car with speed v can pass safe over it. the value of h is

tanθ=

rg

v

2

=

b

h

h=

rg

v

2

b

substituting the values according to given question,

v=48km/h=

3

40

m/s

b=1m

r=400m

g=9.8m/s

2

h=

400∗9.8

3

40

2

∗1

⇒0.0045m

⇒4.54cm