Question

A train is approaching a platform with a speed of 20 km/hr. A bird is on pole at the platform train is 2 kilometre away from the pole breaks are applied so that the train decelerate uniformly,simultaneously the bird also flies toward the train with a velocity 60 kilometre per hour.It touches the nearest point on the train and flies back and back again and so on. The total distance travelled by bird before train stop is?​

Answer 1

Answer:

v =0 and u=20km/hr s=2

we get -400 = 2a(2)

a=-100

time to stop the train

v=u +at

0=20 - 100t

t=1/5hr

so bird will travel for d distance

d=vt

d=60(1/5)

d=12km