Question

A train is moving at a speed of 50m/s and reduces its speed to 10m/s by covering a distance of 240m then find the retardation of the train ​

Answer 1

Given :

• Final velocity, v = 10 m/s
• Initial velocity, u = 50 m/s
• Distance covered, s = 240 m

To find :

• Retardation of the train

According to the question,

➞ v² = u² + 2as

Where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• s = Distance

➞ Substituting the values,

➞ (10)² = (50)² + 2 × a × 240

➞ 100 = 2500 + 480a

➞ 100 - 2500 = 480a

➞ - 2400 = 480a

➞ - 2400 ÷ 480 = a

➞ - 5 = a

• So, the retardation of the train is 5 m/s².

Note : Negative acceleration is also known as retardation.

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Answer 2

Answer:

Given :-

• A train is moving at a speed of 50 m/s and reduces it's speed to 10 m/s by covering a distance of 240 m.

To Find :-

• What is the retardation of the train.

Formula Used :-

★ v² = u² + 2as ★

where,

• s = Distance covered
• u = Initial velocity
• v = Final velocity
• a = Acceleration

Solution :-

Given :

• Final velocity = 10 m/s
• Initial velocity = 50 m/s
• Distance covered = 240 m

According to the question by using the formula we get,

⇒ (10)² = (50)² + 2a(240)

⇒ 100 = 2500 + 480a

⇒ 100 - 2500 = 480a

⇒ - 2400 = 480a

⇒ - 2400 ÷ 480

⇒ - 5 = a

➠ a = - 5 m/s²

Retardation cannot be negetive.

∴ The retardation of the train is 5 m/s² .