A train is moving at the speed of 60 m per second at 10 o'clock
a.M. At 80 m per second at 10:02 am . Assuming that the train moves along striaght track and the acceleration is constant , the value of acceleration is
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for A train is moving at the speed of 60 m per second at 10 o'clock a.M. At 80 m per second at 10:02 am . Assuming that the train moves along striaght track and the acceleration is constant , the value of acceleration is...
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The acceleration is 40 m\s
Explanation:
Given:
initial velocity (u) = 60m\s
time taken (t1) = 10:00 am
final velocity (v) = 80m\s
time taken(t2) = 10:02 am
total time taken (t) = t1 - t2 = 10:00 -10:02 = 2 minutes
= 120 seconds
acceleration (a) = ?
a = v-u\t
a = 80 - 60\ 120
therefore, a = 40 m per second square
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