the last term of the series x², x ,1,......to 31 term is solve it with GP
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Answered by
1
Answer: x^-28
Step-by-step explanation:
n = 31 (no.of terms)
a= x^2 ( first term in the given series)
r= 1/x( common ratio)
t31 =ar^30 (tn=ar^n-1)
t31=x^2/x^30
t31= x^-28
Answered by
1
r=a2/a1
=x/x^2
=1/x
a31=ar30
=x^2×(1/x^30)
=1/x^28 I hope it helps you
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