A train is moving with 40 kmph slowly came to rest after 3 min It has
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Answer:
It covered a distance of 1999.9999 metres (or) 1.99999 kilometers with a deceleration of 0.0617 m/s².
Explanation:
Distance=Speed×Time
Speed=40 kmph =(40×1000)÷3600= 11.11111 m/s
Time= 3 min = 3 × 60 sec= 180 Secs
Distance= 11.1111111×180= 1999.999 metres = 1999.999÷1000 = 1.99999kilometres.
Deceleration = Distance÷(time)² = 1999.999÷(180)² = 0.0617 m/s².
That's it.
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