Question

A train is moving
with a velocity of
108km/h and it take 4s to stop after the brakes are applied
Calculate the
brakes on the train if it's mass is 10000kg
​

Answer 1

Answer:

Explanation:

Correct Question,

A train is moving with a velocity of 108 km/h and it takes 4s to stop after the brakes are applied. Calculate the force exerted by the brakes on the train if its mass is 10000 kg.​

Solution,

Here, we have

Initial velocity, u = 108 km/h = 108 × 5/18 = 30 m/s

Final velocity, v = 0 m/s (As train stops)

Time taken, t = 4 seconds

Mass, m = 10000 kg

At first we have to find acceleration,

According to the 1st equation of motion,

We know that,

v = u + at

⇒ 0 = 30 + a × 4

⇒ - 30 = 4a

⇒ - 30/4 = a

⇒ a = - 7.5 m/s².

Here, the acceleration of train is - 7.5 m/s².

Now, the force exerted, F

According to Newton's 2nd law,

We know that,

F = ma

⇒ F = 10000 × (- 7.5)

⇒ F = - 75000 Newton.

Hence, the force exerted by the brakes is - 75000 Newton.

Answer 2

Answer:

Answer:

Explanation:

Correct Question,

A train is moving with a velocity of 108 km/h and it takes 4s to stop after the brakes are applied. Calculate the force exerted by the brakes on the train if its mass is 10000 kg.​

Solution,

Here, we have

Initial velocity, u = 108 km/h = 108 × 5/18 = 30 m/s

Final velocity, v = 0 m/s (As train stops)

Time taken, t = 4 seconds

Mass, m = 10000 kg

At first we have to find acceleration,

According to the 1st equation of motion,

We know that,

v = u + at

⇒ 0 = 30 + a × 4

⇒ - 30 = 4a

⇒ - 30/4 = a

⇒ a = - 7.5 m/s².

Here, the acceleration of train is - 7.5 m/s².

Now, the force exerted, F

According to Newton's 2nd law,

We know that,

F = ma

⇒ F = 10000 × (- 7.5)

⇒ F = - 75000 Newton.

Hence, the force exerted by the brakes is - 75000 Newton.

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