A train is moving with a velocity of 90 km per hour it is brought to stop by applying the brakes which produce a retardation of 0.5 metre per second square find the velocity after 10 seconds and the time taken by the train to come to rest
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Answered by
5
Hi..
u=90km/h = 90×5/18 = 25m/sec
v= 0m/s
a = -0.5m/s²
then using first equation of motion ,
v=u+at
0 = 25+(-0.5)t
0=25-0.5t
0.5t=25
t= 25/0.5 = 50 seconds ..
Hope this helps u!!
u=90km/h = 90×5/18 = 25m/sec
v= 0m/s
a = -0.5m/s²
then using first equation of motion ,
v=u+at
0 = 25+(-0.5)t
0=25-0.5t
0.5t=25
t= 25/0.5 = 50 seconds ..
Hope this helps u!!
Answered by
1
Answer:
i) v = 0
a = - 0.5 m/s²
t = ?
u = 90 × 5/18 m/s = 25 m/s
v = u + at
0 = 25 + (- 0.5) t
0= 25 - 0.5t
0.5 t = 25
t = 25 / 0.5
t = 50 s
ii) u = 90 km/h = 90 × 5/18= 25 m/s
a = - 0.5 m /s²
t = 10 s
v = u + at
v = 25 + ( - 0.5) 10
v = 25 - 5 = 20 m/s
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