Question

a train is moving with an initial velocity of 30m/s the brakes are applied so as produce a uniform acceleration of 1.5 m/s sq calculate the time in which it come to rest

Answer 1

S the train stops v=0 also a=-1.5m/s²
v=u+at
0=30+-1.5×t
t=-30/-1.5
t=20s
So the train comes in rest with 20s
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Answer 2

initial velocity = 30m/s
final velocity = 0m/s
Acceleration = -1.5m/s (as the train comes to rest)

using defination of acceleration (1st equation of motion)
v = u+ at
0 = 30+ (-1.5)(t)
1.5t = 30
t = 30/1.5
= 20


So, the time taken by the train to come to rest was 20 seconds.