a train is moving with uniform acceleration of 4ms-2 starting from rest. velocity after the 15 sec is
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Answered by
2
Answer:
Velocity after 15s = 60m/s
Given:
Initial Velocity (u) = 0m/s
Final Velocity (v) = ?
Acceleration (a) = 4ms⁻²
Time (t) = 15s
Explanation:
Using the first equation of motion,
v = u + at
⇒ v = 0 + (4 × 15)
⇒ v = 60
∴ Velocity after 15 seconds = 60m/s
More help content:
- First equation of motion:
v = u + at
- Second equation of motion:
s = ut + 1/2 × at²
- Third equation of motion:
2as = v² - u²
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Havishmadhava:
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Answered by
3
Answer:
Velocity after 15s = 60m/s
Given:
Initial Velocity (u) = 0m/s
Final Velocity (v) = ?
Acceleration (a) = 4ms⁻²
Time (t) = 15s
Explanation:
Using the first equation of motion,
v = u + at
⇒ v = 0 + (4 × 15)
⇒ v = 60
∴ Velocity after 15 seconds = 60m/s
More help content:
First equation of motion:
v = u + at
Second equation of motion:
s = ut + 1/2 × at²
Third equation of motion:
2as = v² - u²
Explanation:
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