a train is traveling at the speed of 90kmh-1 brakes are applied so as to produce a uniform acceleration -o.5ms-2 . find how far the train will gobefre it is brought to rest.<br /><br /><br />
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u=90kmph=90×5÷18=25 m/s
a=-0.5m/s^2
v=0
v=u+at
0=25+(-0.5)t
-25=-0.5×t
t=50s
distance:
s=ut+1/2at^2
s=25(50)+(0.5)(-0.5)(50)(50)
s=1250-625
s=625 metres
a=-0.5m/s^2
v=0
v=u+at
0=25+(-0.5)t
-25=-0.5×t
t=50s
distance:
s=ut+1/2at^2
s=25(50)+(0.5)(-0.5)(50)(50)
s=1250-625
s=625 metres
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