a train is traveling in an speed of 90 km per hour brakes are applied so as to produce and uniform acceleration of minus 0.5 m second square find how far the train will go before it brought in rest
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U=90km h-1 =90×(5/18)=25ms-1
A=-0.5 ms-2
Train brought to rest ,so final speed v=0
Form third equation of mothin v2=u2+2as
0=(25)2+2×0.5×s
=624-s
=625m
Mark it plss
A=-0.5 ms-2
Train brought to rest ,so final speed v=0
Form third equation of mothin v2=u2+2as
0=(25)2+2×0.5×s
=624-s
=625m
Mark it plss
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