A train is travelling at a speed of 60 km/ h. Brakes are applied so as to produce a uniform acceleration of −0.5 m /s2. Find how far the train will go before it is brought to rest.
Answers
Answered by
11
Answer:
The train will go 277.78m before it is brought to rest.
Explanation:
Here,
Initial velocity, u=60km/h=16.67m/s
Final velocity, v=0 [As the body is at rest then]
Acceleration, a=-0.5 m/s^2
Distance travelled, s=?
We know,
v^2=u^2 +2as
-2as=u^2
-s=u^2 / 2a
s=(16.67^2)/(2×0.5)
s=277.78
The distance travelled by the train would be 277.78m.
Answered by
1
Answer:
277.78
Explanation:
Initial velocity, u=60km/h=16.67m/s
Final velocity, v=0 [As the body is at rest then]
Acceleration, a=-0.5 m/s^2
Distance travelled, s=?
We know,
v^2=u^2 +2as
-2as=u^2
-s=u^2 / 2a
s=(16.67^2)/(2×0.5)
s=277.78
The distance travelled by the train would be 277.78m.
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