A train is travelling at a speed of 60km/h. Brakes are applied so as to produce a uniform acceleration of -0.6m/s2.Find how far the train will go before it is brought to rest.
Answers
Answered by
1
Answer:
59.4
Step-by-step explanation:
60.0
0.6
_____
59.4
Answered by
1
Answer:
velocity of train = 60km/h
= 60 × 5/18
=50/3 m/s
Acceleration of train = -0.5 m/s² -
Final velocity = 0 m/s ( as train come to rest)
Distance covered by train before it is brought
to be rest.
By using 3rd equation of motion
v² = u² +2as
0² = (50/3)² + 2 × (-0.5) × s
0 = 2500/9 + (-1)× s
s = 2500/9
s = 277.7 m
It is correct
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