A train is travelling at a speed of 70 km h–1. Brakes are applied so as to produce a uniform acceleration of – 0.5 m s-2. Find how far the train will go before it is brought to rest.
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Answer:
v2-u2=2as
v2-u2/2a=s
v=final velocity=o
u=initial velocity= 75kmph=20.83mps
substituting values,
(0)2-(20.83)2=2*-0.5
=0-433.8889=-1
therefore it goes 433.8889m.
Explanation:
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