Question

A train is travelling at a speed of 90 km h-1 . Brakes are applied so as to produce a uniform acceleration of, -0.5 ms-2 . Find how far the train will go before it is brought to rest.​

Answer 1

GIVEN:

initial velocity (u)=90 km /hr= 90×5/18=25m/s

decceleration= -0 .5 m/s²

final velocity (v)=0

TO FIND:

Distance=??

SOLUTION:

${v}^{2} = {u}^{2} + 2as \\ {v}^{2} = {u}^{2} - 2as \\ {u}^{2} = 2as \\ s = 625m$

I hope this helps ( ╹▽╹ )

Answer 2

Answer:

A train travelling at the speed of 90 km/h

brakes are applied to produce uniform acceleration -0•5 =90/-0•5=1•2 meters

-1•2× -2

2•4