a train is travelling at a speed of 90 km h -1 break are applying so as to produce a uniform accrration of 0.5 ms-2 find how far the train will go before it is brought to rest.
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Initial speed = u = 90km/h = 90×1000/1×3600 = 25m/s
Final speed = v = 0m/s
Acceleration = a = (- 0.5m/s²)
Distance = s = ?
V²-u² = 2as
(V²-u²)/2a = s
(0-625)/2×-0.5 = s
-625/-1 = s
625 m = s
Final speed = v = 0m/s
Acceleration = a = (- 0.5m/s²)
Distance = s = ?
V²-u² = 2as
(V²-u²)/2a = s
(0-625)/2×-0.5 = s
-625/-1 = s
625 m = s
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