A train is travelling at a speed of 90 km/h. brakes are applied to produce uniform acceleration of -0.5 m/s^ .Find the distance travelled by the train .
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Answered by
39
As given here -
u = 90 km/h
= 90× 1000/ 60×60
= 90000/360
= 25m/s
a = -0.5 ms^-2
v = 0 m/s
By the third equation of motion , we obtained
2as = v^2 - u ^2
=>2 × ( -0.5) (s ) = (0)^2 - ( 25 )^2
=> -1 s = - 625
=> s = 625 m
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u = 90 km/h
= 90× 1000/ 60×60
= 90000/360
= 25m/s
a = -0.5 ms^-2
v = 0 m/s
By the third equation of motion , we obtained
2as = v^2 - u ^2
=>2 × ( -0.5) (s ) = (0)^2 - ( 25 )^2
=> -1 s = - 625
=> s = 625 m
★Please mark it as brainliest and don't forget to press heart icon
sarayulemon:
wait wait wait
3rd equation of motion is 2as=v^-u^
ooooo
i understood
sorry sorry sorry
thank u
my pleasure
Answered by
11
Given :
u = 90km/hr = 25m/s²
a = -0.5 m/s²
v= 0m/s²
S = ?
so by using equation of motion :
v²-u²=2as
s=(0²-25²)/(2x-0.5)
s=625 m
So, the train will go 625 m
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