a train is travelling at a speed of 90 km/h brakes are applied in the train so as to produce a uniform retardation of 0.5m/s(2)(square). find the distance the train will travel before it is brought to rest?
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initial velocity of train(u)= 90kph=90x 5/18=25 m/s
final velocity(v)=0
retardation =- 0.5 m/s²
distance traveled (s)
by equation of motion
v²-u²=2as
-625 = -2 x5/10 x s
s= 625m
total distance traveled by train before stopping is 625m
final velocity(v)=0
retardation =- 0.5 m/s²
distance traveled (s)
by equation of motion
v²-u²=2as
-625 = -2 x5/10 x s
s= 625m
total distance traveled by train before stopping is 625m
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