Question

A train is travelling at a speed of 90 km per hour brakes are applied so as to produce a uniform acceleration of -0.5 m per second find how far will train go before it is brought to rest

Answer 1

Answer: 625meter

Explanation:

Answer 2

Answer:

✤ Initial velocity (u) = 90 km/h

→ 90 × 5/18 = 25 m/s

✤ Acceleration (a) = - 0.5 m/s

✤ Final velocity (v) = 0

→ By using third equation of motion,

❖ $\large\fbox\red{\sf 2as = v^2 - u^2}$

→ $\sf{2(-0.5)s = (0)^2 - (25)^2}$

→ $\sf{-1 s = -625}$

→ $\large\fbox\purple{\sf s = 625\:m}$

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❖ Three equations of motion :-

$\textsf{v = u + at}$

$\sf{s = ut + \frac{1}{2} at^2}$

$\sf{2 as = v^2 - u^2}$

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