Question

a train is travelling at a speed of 90 km per hour brakes are applied so as to produce a uniform acceleration of - 0.5 metre per second square find how far the train will go before it is brought to rest
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Answer 1

Answer:

Explanation:

We can use the equation of motion

v^2 = u^2 + 2as

Where v = final velocity

U = initial velocity

A = acceleration

S = distance travelled

As the train has to stop v = 0

U = 90km/h = 90*(5/18) = 25m/s

A = -0.5m/s^2

S = ?

Using the equation

0 = (25)^2 + 2(-0.5)(S)

0= 625 -1(S)

-625 = -S

Distance travelled before stopping = 625 metre

Answer 2

Explanation:

..here is ur ans...

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