Question

 A train is travelling at a speed of 90 km per hour.Brakes are applied so as to produce a uniform acceleration of -0.5 metre per second square. Find how far the train will go before it is brought to rest.


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Answer 1

Answer:

answer is 625m

Explanation:

firstly find time taken to stop the car

by identity v=u +at

           u = 90 × 5/18      ( converting into m/s)

              = 25m/s

            a = -0.5 m/s^2

            v = 0m/s

  0 = 25 - 0.5 t

 t = 50s

now find distance by  s = ut + 1/2 at^2

    s = 25 × 50 - 1/2 × 0.5 ×50 ×50

    s = 625m