Question

A train is travelling at a speed of 90 km per hour. Brakes are applied so as to produce a uniform acceleration of -0.5 metre per square. Find how far the train will go before it is brought to rest

Answer 1

So we have to find

v_________u=90km/hr=25m/sec

x=distance a=-.5m^2

So

By equatio

V^2=u^2+2as

V=0

U=25

a=-. 5

S=x

0^2=25^2+2*(-.5)*x

0=625-x

X=625 m your answer

Answer 2

Answer:

speed of train=90km/hr

=25m/s

acceleration=-0.5m/s^2

Explanation:

v^2-u^2=2as

0-25^2=2×5/10×s

-625=s (the negative sign is due to retardation of train)

therefore s=625m

Therefore the train will go 625m far before brought to rest