Question

a train is travelling at a speed of 90 km per hour day card applied to produce and uniform acceleration of - 0.5 metre per second square find how far will the train go before the train brought to the rest

Answer 1

Here,
initial speed,u=90km/h
                      =90×(5/18)
                      =25m/s
acceleration,a=-0.5m/s²
Train is brought to rest,so final speed,v=0
From third equation of motion,v²=u²+2as
0=(25)2+2×0.5×s
0=625 - s
s=625 m