Question

A train is travelling at a speed of 90km/h.brakes are applied so as to produce a uniform acceleration of -0.5m/s².find how far the train will go before it is brought to rest

Answer 1

V₀ = 90 km/h = 25 m/s
V = 0   (the train stopped
a = - 0,5 m/s²
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S - ?

S = (V²-V₀²) / (2·a)
S = (0² - 25² / (2·(-0,5)) = (- 625) / ( - 1) = 625 m

Answer 2

Answer:

Distance = 625 m.

Explanation:

Question-

A train is travelling at a speed of 90km/h. Brakes are applied so as to produce a uniform acceleration of -0.5m/s².Find how far the train will go before it is brought to rest.

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Given Information -

• Initial velocity (u) =90km/hr = 25m/s
• Acceleration (a) = - 0.5 m/s²
• Final velocity(v) = 0 m/s

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Required Answer-

• Distance(s) .

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Solution-

Formula to be Implemented here-

$\implies$ $\underline{\boxed{\sf\purple{2as = v² -u² }}}$

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Answer -

$\implies$ Replacing values with formula.

$2as = {v}^{2} - {u}^{2} \\ \\ 2 \times ( -0 .5 \times s)= {0}^{2} - {25}^{2} \\ \\ - 1s = - 2 {5}^{2} \\ \\ - 1s = - 625 \\ \\ 1s = 625$

So distance is 625 m.