Question

A train is travelling at a speed of 90km/h.Brakes are applied so as to produce a uniform acceleration of-0.5m/s.Find how far the train will go before it is brought to rest

Answer 1

Heya there!
Here is the answer...

Speed = 90km/h
= 5/18 × 90
= 25ms^-1
v = 0
a = - 0.5ms^-2

From equation 3rd

v^2 = u^2 + 2as

(0)^2 = (25)^2 + 2 × (- 0.5) × s

0 = 625 + (- 1.0)s

0 - 625 = - 1.0

S = 625m ans.

Hope, it will help you...

MARK ME AS BRAINLIST

Answer 2

Given:

$u=90Km/hr$ or$90*\frac{5}{18} = 25m/s$

Uniform acceleration =$-0.5m/s^{2}$

v = 0 (since, the train is brought at rest)

$v^{2}= u^{2} +2as\\=>625+2*-0.5*s = 0\\=>-s=-625\\=>s=625$

Therefore, total distance traveled by the train is 625 m

Here, formula applied are:-

$v^{2}= u^{2} +2as$

Plzz mark it as the brainliest one