Question

a train is travelling at a speed of 90km/hr . breaks are applied so as to produce uniform acceleration of -0.5m/s². find how far the train will go before it is bought to rest. ​

Answer 1

Answer:

u= 90 kmper hr

change units to m/s

so u = 90× 5÷ 18= 25 m/s

v= o

a= 0.5m/s2

using formula

v2= u2 +2as

v is zero so

- u2= 2as

(25×25) =2×0.5×s

s=625m

Answer 2

Distance, s = 520.8 m

Explanation:

It is given that,

Initial speed of train, u = 90 km/h = 25 m/s

When brakes are applied, the uniform acceleration of the train is -0.6 m/s². We have to find the distance covered by the train before it come to rest.

Using third equation of motion :

s = 520.8 m

So, the train will go 520.8 m before coming to rest. Hence, this is the required solution.