A train is travelling at a speed of 90km per hour . Brakes are applied so as to produce a uniform acceleration of -0.5 m s . Find how far the train will go before it is brought to rest?
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Answer:
625 m
Explanation:
Given that
The speed of the train = 90 km/hr
convert the speed into m/s by multiplying it with 5/18
=> speed = 90 × 5/18
=> Speed of the train before application of brakes = 25 m/s
Given that the retardation( -ve acceleration) of the train = -0.5 m/s
here -ve symbol indicates acceleration in opposite direction.
Now, From
v² - u² = 2as
=> 0 - (25)² = 2(-0.5)s
=> -625/-0.5 = 2s
=> 1250 = 2s
=> s = 625 m
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