A train is travelling at speed 90 km per hour . Breaks are applied so as to produce uniform acceleration of -0.6 metre per second ^2. Find how far train will go before it is brought to rest
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initial velocity=90kmh-¹=25ms-¹
final velocity=0,ms-¹
retardation=(-.6)ms-²
a=v-u/t
-.6=0-25/t
T=(-25)/(-0.6)
T=41.6 sec
2as=v²-u²
2×(-0.6)×s=0²-5²
-1.2*s=-25
s=(-25)/(-1.2)=20.8m
final velocity=0,ms-¹
retardation=(-.6)ms-²
a=v-u/t
-.6=0-25/t
T=(-25)/(-0.6)
T=41.6 sec
2as=v²-u²
2×(-0.6)×s=0²-5²
-1.2*s=-25
s=(-25)/(-1.2)=20.8m
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