A Train is travels 360 km at a uniform speed .if the speed has been 5km/h more.it would had taken 1 hour less for the same journey. find the speed of the train
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360=XxY (1)
360= (X+5)x(Y-1) (2)
360 XY-X+5Y-5
from 1st XY=360 and y=360/X
then,
360=360-X+(5×360)/X -5
X^2+5X-1800=0
X=40
360= (X+5)x(Y-1) (2)
360 XY-X+5Y-5
from 1st XY=360 and y=360/X
then,
360=360-X+(5×360)/X -5
X^2+5X-1800=0
X=40
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