how to solve it....
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mid point of (2,0) and (0, 2/9) is (1,1/9)
by equating (1,1/9) with (1,p/3)
we get
p/3=1/9 therefore p=1/3
now we get the point (-1,3p) as (-1,1)
x= -1 and y=1. is a solution of the line
5x+3y+2=0
therefore (-1,1) is a point on the line
5x+3y+2=0
by equating (1,1/9) with (1,p/3)
we get
p/3=1/9 therefore p=1/3
now we get the point (-1,3p) as (-1,1)
x= -1 and y=1. is a solution of the line
5x+3y+2=0
therefore (-1,1) is a point on the line
5x+3y+2=0
Ãmanchavan:
thanks
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