a train leaves meerut at 7.30 a.m. and reaches Delhi 9.45 a.m. what is distance between meerut and Delhi if the average speed of the train is 32km/h
Answers
Answered by
1
Answer:
Step-by-step explanation:
Time taken = 9:45 - 7:30
= 2 hrs 15 mins
= 2 + 15/60 hr
= 2 + 1/4
= 2.25 hrs
Speed = 32km/h
Distance = speed × time
= 32 × 2.25 = 72 kms
Answered by
0
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
Time taken = 9:45 - 7:30
= 2 hrs 15 mins
= 2 + 15/60 hr
= 2 + 1/4
= 2.25 hrs
Speed = 32km/h
Distance = speed × time
= 32 × 2.25 = 72 kms
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