a train leaves new Delhi at 1915 hours and arrives mathura at 2205 distance between two stations in 144 km .find the speed of the train.
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Answered by
8
speed= distance/time
time taken for the journey = 2hrs 50 minutes
=> (2×3600)+(50×60) = 7200+3000 = 10200 seconds
distance covered = 144000 meters
speed = 144000/10200
=> 1440/102 = 14.12 m/s
time taken for the journey = 2hrs 50 minutes
=> (2×3600)+(50×60) = 7200+3000 = 10200 seconds
distance covered = 144000 meters
speed = 144000/10200
=> 1440/102 = 14.12 m/s
Answered by
6
train leaved ar 19hr 15 min and arrived at 22he 05 min
time taken.=2hr50min
=2+50/60
=12+5 /7
=17/7 Hr
Now total distance travelled=144Km.
So Speed =144÷17/7
=144×7/17
=59.294... Km/Hr (approx)
Hope this is what you were looking for...
Regards,
Leukonov...
time taken.=2hr50min
=2+50/60
=12+5 /7
=17/7 Hr
Now total distance travelled=144Km.
So Speed =144÷17/7
=144×7/17
=59.294... Km/Hr (approx)
Hope this is what you were looking for...
Regards,
Leukonov...
Leukonov:
Plzz mark as Brainliest...
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