A train leaves station A toward station B,24 km away and has to reach B in half an hour.If it travels at 45 km/hr for the first quarter if an hour,at what speed must it travel for the rest of the journey ti complete it travel for the rest of the journey to complete it in time?
please friends help me in this..
Answers
Answered by
19
Distance covered in first quarter of an hour i.e in 1/4 hour=45*(1/4) km
Remaining distance=24-(45/4)=51/4
Remaining time=1/2-1/4=1/4 hour
So,required speed=(51/4)/(1/4)=51 km/hr (Ans)
Remaining distance=24-(45/4)=51/4
Remaining time=1/2-1/4=1/4 hour
So,required speed=(51/4)/(1/4)=51 km/hr (Ans)
sharon00:
thank you
Answered by
3
distance between A and B is 24 km
time should be taken 30mins means half an hour
so distance will be 45/4 at 45km/hr time taken is 15mins
now distance left= 51/4km
time should be taken 30 -15 =15mins or 1/4hr
speed will be (51/4)/(1/4) =51km/hr
time should be taken 30mins means half an hour
so distance will be 45/4 at 45km/hr time taken is 15mins
now distance left= 51/4km
time should be taken 30 -15 =15mins or 1/4hr
speed will be (51/4)/(1/4) =51km/hr
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