Question

A train moves a distance of 10m with the a constant speed of 40 m/s and moves the next 5m with a constant speed of 30 m/scalculate its its average speed

Answer 1

Answer:

Given:

Train first moves with 40 m/s for 10 metres and then with 30 m/s for 5 metres .

To find:

Average velocity

Definitions:

Average velocity is the ratio of total displacement to the total time taken.

$v \: avg = \frac{displacement}{time}$

Calculation:

v avg. = total displacement/time

$v \: avg \: = \frac{10 + 5}{ \frac{10}{40} + \frac{5}{30} }$

=> v avg. = 15/(0.25 + 0.166)

=> v avg. = 15/(0.416)

=> v avg. = 36.057 m/s.

So the final answer is

$\huge{\boxed{v \: avg \: = 36.057 \: m {s}^{ - 1} }}$

Answer 2

✰ Question

➵ Given above

✰ Answer :-

$\leadsto \red{ \boxed{\sf \blue{average \: speed \: }= 36 \: \frac{m}{s} }} \:$

✰ Step - by - step explanation :-

Given that ,

• Distance travelled by train = 10 m

• speed of train = 40 m/s

• After it next 5 m moves with speed 30 m/s

Hence find average speed ?

→ time taken to cover 10 m is = 10/40 s

→ time taken to cover 5 m is 5/30 s

we know that ,

$\leadsto \boxed{\sf \red{ average \: speed} = \green{ \frac{displacement}{time} }} \\ \\ \leadsto \sf average \: speed \: = \frac{10 + 5}{ \frac{10}{40} + \frac{5}{30} } \\ \\ \leadsto \sf \: averge \: speed = \frac{15}{ \frac{3 + 2}{12} } \\ \\ \leadsto \red{ \boxed{\sf \blue{average \: speed \: }= 36 \: \frac{m}{s} }}$

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