Question

a train moves from a railway station and moving with uniform acceleration attains speed of 40km/h in 10min. Find Acceleration​

Answer 1

As the train started from a railway station, so initial velocity of train, u = 0

Final velocity of train, v = 40 kmph

Final velocity, v = 40 × 5/18 = 11.11 m/s

Assuming uniform acceleration of ‘a’ m/second square

Time taken by train to get it's final velocity, t = 10 minutes = 600 seconds

Using first equation of motion,

V = u + at

11.11 = 0 + a×600

a = 11.11/600 = 0.0185 m/second square.

So, required acceleration , a = 0.0185 m/second square.

Answer 2

☺HOLA☺

Here we have,

Initial velocity,u=0

Final velocity,v=40 km/hr=11.11 m/s

Time,t=10 hr=60×10=600 s

Acceleration = ? (a)

We know that,

v=u+at

➡40 = 0 + a ×10

➡11.11 = a × 600

➡a = 11.11/600

➡a=0.0185 m/s^2

HOPE IT HELPS UHH

#CHEERS