Question

Please answer it quickly please
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in a certain operation 358gram of TiCl4 is reacted with 96 gram of Mg. Calculate %yield of Ti if 32 gram of Ti is actually obtained.( atomic weight of Ti=48)

Answer 1

mass of TiCl4 = 358g

mass of Mg reacted = 96gm

mass of Ti is actually obtained = 32gm

molecular mass of TiCl4 = 48 + 4 × 35.5 = 190g/mol

see the reaction...

$TiCl_4+2Mg\rightarrow Ti + 2MgCl_2$

here we see 1 mole of TiCl4 reacts with 2 mole of Mg

or, 190g of TiCl4 reacts with 48g of Mg.

or, 358g of TiCl4 reacts with 48/190 × 358 = 90.44g but here present mass of Mg is 96g.

so, TiCl4 is limiting reagent.

now, 1 mole of TiCl4 produce 1 mole of Ti

or, 190g of TiCl4 produce 48g of Ti

or, 358g of TiCl4 produces 48/190 × 358 = 90.44gm

now % yield = experimental value /theoretical value × 100

= 32/90.44 × 100

= 35.38%