A train moves from rest to a speed of 25 m/s in 30 seconds. What is the magnitude of its acceleration?
Answers
Answered by
120
Given:-
- Initial velocity ,u = 0m/s
- Final velocity ,v = 25m/s
- Time taken ,t = 30
To Find:-
- Magnitude of Acceleration ,a
Solution:-
we have to calculate the magnitude of acceleration.
As we know that acceleration is defined as the rate of change in velocity .
- a = v-u/t
where
- v is the final velocity
- a is the acceleration
- u is the initial velocity
- t is the time taken
Substitute the value we get
a = 25-0/30
a = 25/30
a = 0.833 m/s²
- Hence, the acceleration of the train is 0.833 m/s².
Answered by
52
Given that , A train moves from rest to a speed of 25 m/s in 30 seconds .
Exigency To Find : The magnitude of Acceleration of train .
⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀
⠀⠀⠀⠀⠀Given that ,
- The initial velocity ( u ) of train is 0 m/s [ as , train starts from rest ] .
- The final velocity ( v ) of train is 25 m/s .
- Total Time taken ( t ) is 30 seconds .
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀Finding Magnitude of Acceleration of Train :
⠀⠀⠀Here , v is the final velocity , u is the Initial velocity , t is the total time taken and a is the Acceleration.
⠀⠀⠀⠀⠀⠀
- Here, a denotes Magnitude of Acceleration which is 0.833 m/s²
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