Question

A train moving at speed 72km/hr brought to rest 40 second find the relation and the distance coverd

Answer 1

speed=72*5/18=20 m/s

acceleration= (V-U)/t= (0-20)/40= -0.5 m/s^2

S=ut+ 1/2at^2

S=20*40+ 1/2*(-0.5)*40^2 =400 m