A train moving at the rate of 72 km per hour is to be stopped in 200 m the Retardation required will be
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72 kmph = 72 × 5/18 = 20 m/s
Retardation (a) is given as
a = u^2 / (2S)
= (20)^2 / (2 × 200)
= 20 m/s^2
Retardation required is 20 m/s^2
Retardation (a) is given as
a = u^2 / (2S)
= (20)^2 / (2 × 200)
= 20 m/s^2
Retardation required is 20 m/s^2
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