Prove that in a right angled triangle square of hypotenuse is equal to the sum of its other two sides.
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Answered by
5
We know that square of hypotenuse is equal to the sum of its other two sides.
H^2= P^2+B^2
H^2= x^2+x^2
H^2=2x^2
H/2=x^2
√H/2=x.
Hope it helps you
H^2= P^2+B^2
H^2= x^2+x^2
H^2=2x^2
H/2=x^2
√H/2=x.
Hope it helps you
Answered by
4
hope u hav got ur answer
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